{{c1:: \(\sum_{j = 1}^{n} \sum_{k = \textbf{j}}^{n} 1\)}} \(=\) {{c2:: \(\sum_{j = 1}^n (n - j + 1) = \frac{n(n + 1)}{2}\)}}
Note 1: ETH::A&D
Deck: ETH::A&D
Note Type: Horvath Cloze
GUID:
modified
Note Type: Horvath Cloze
GUID:
u2lDE>&5/e
Before
Front
Back
{{c1:: \(\sum_{j = 1}^{n} \sum_{k = \textbf{j}}^{n} 1\)}} \(=\) {{c2:: \(\sum_{j = 1}^n (n - j + 1) = \frac{n(n + 1)}{2}\)}}
inner loop depends on outer
After
Front
{{c1:: \(\sum_{j = 1}^{n} \sum_{k = \textbf{j} }^{n} 1\)}} \(=\) {{c2:: \(\sum_{j = 1}^n (n - j + 1) = \frac{n(n + 1)}{2}\)}}
Back
{{c1:: \(\sum_{j = 1}^{n} \sum_{k = \textbf{j} }^{n} 1\)}} \(=\) {{c2:: \(\sum_{j = 1}^n (n - j + 1) = \frac{n(n + 1)}{2}\)}}
inner loop depends on outer
Field-by-field Comparison
| Field | Before | After |
|---|---|---|
| Text | {{c1:: \(\sum_{j = 1}^{n} \sum_{k = \textbf{j}}^{n} 1\)}} \(=\) {{c2:: \(\sum_{j = 1}^n (n - j + 1) = \frac{n(n + 1)}{2}\)}} | {{c1:: \(\sum_{j = 1}^{n} \sum_{k = \textbf{j} }^{n} 1\)}} \(=\) {{c2:: \(\sum_{j = 1}^n (n - j + 1) = \frac{n(n + 1)}{2}\)}} |
Note 2: ETH::A&D
Deck: ETH::A&D
Note Type: Horvath Cloze
GUID:
modified
Note Type: Horvath Cloze
GUID:
NU;6ob<^n3
Before
Front
{{c1:: \(\sum_{i = 1}^{n} \sum_{k = 1}^{\textbf{i}} 1\)}} \(=\) {{c2:: \(\sum_{i = 1}^n i = \frac{n(n + 1)}{2}\)}}
Back
{{c1:: \(\sum_{i = 1}^{n} \sum_{k = 1}^{\textbf{i}} 1\)}} \(=\) {{c2:: \(\sum_{i = 1}^n i = \frac{n(n + 1)}{2}\)}}
inner loop depends on outer
After
Front
{{c1:: \(\sum_{i = 1}^{n} \sum_{k = 1}^{\textbf{i} } 1\)}} \(=\) {{c2:: \(\sum_{i = 1}^n i = \frac{n(n + 1)}{2}\)}}
Back
{{c1:: \(\sum_{i = 1}^{n} \sum_{k = 1}^{\textbf{i} } 1\)}} \(=\) {{c2:: \(\sum_{i = 1}^n i = \frac{n(n + 1)}{2}\)}}
inner loop depends on outer
Field-by-field Comparison
| Field | Before | After |
|---|---|---|
| Text | {{c1:: \(\sum_{i = 1}^{n} \sum_{k = 1}^{\textbf{i}} 1\)}} \(=\) {{c2:: \(\sum_{i = 1}^n i = \frac{n(n + 1)}{2}\)}} | {{c1:: \(\sum_{i = 1}^{n} \sum_{k = 1}^{\textbf{i} } 1\)}} \(=\) {{c2:: \(\sum_{i = 1}^n i = \frac{n(n + 1)}{2}\)}} |
Note 3: ETH::DiskMat
Deck: ETH::DiskMat
Note Type: Horvath Classic
GUID:
added
Note Type: Horvath Classic
GUID:
gYg{Yu8NW0
Previous
Note did not exist
New Note
Front
Are no roots equivalent to irreducibility for a polynomial extension?
Back
Are no roots equivalent to irreducibility for a polynomial extension?
No, the factors could all be irreducible polynomials.
Field-by-field Comparison
| Field | Before | After |
|---|---|---|
| Front | Are no roots equivalent to irreducibility for a polynomial extension? | |
| Back | No, the factors could all be irreducible polynomials. |