Every set of \(n\) linearly independent vectors spans {{c1:: \(\mathbb{R}^n\)}}.
Note 1: ETH::LinAlg
Deck: ETH::LinAlg
Note Type: Horvath Cloze
GUID:
added
Note Type: Horvath Cloze
GUID:
Bs.wqkt>9r
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Front
Back
Every set of \(n\) linearly independent vectors spans {{c1:: \(\mathbb{R}^n\)}}.
This is from the script.
Field-by-field Comparison
| Field | Before | After |
|---|---|---|
| Text | Every set of \(n\) {{c1:: linearly independent}} vectors spans {{c1:: \(\mathbb{R}^n\)}}. | |
| Extra | <i>This is from the script.</i> |
Note 2: ETH::LinAlg
Deck: ETH::LinAlg
Note Type: Horvath Classic
GUID:
added
Note Type: Horvath Classic
GUID:
s1Oa?:={wu
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Does \(Av = v\) mean \(1\) is an eigenvalue of \(A\)?
Back
Does \(Av = v\) mean \(1\) is an eigenvalue of \(A\)?
No, we need to have \(v \neq 0\) to have that relationship hold!
Field-by-field Comparison
| Field | Before | After |
|---|---|---|
| Front | Does \(Av = v\) mean \(1\) is an eigenvalue of \(A\)? | |
| Back | <b>No</b>, we need to have \(v \neq 0\) to have that relationship hold! |