Note 1: ETH::DiskMat
Note Type: Horvath Cloze
GUID:
Cx
Before
Front
Back
After
Front
Back
Proof sketch:
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Consider a nonzero, nonunit \(a \in R\).
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If a is irreducible, we are done.
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Otherwise, \(a = bc\) with both \(b,c\) nonunits.
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By the Euclidean property, we may assume\(\delta(b), \delta(c) < \delta(a)\).
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If either factor is reducible, factor it further.
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This process must terminate, since \(\delta\) takes values in \(\mathbb{N}\) and strictly decreases.
Field-by-field Comparison
| Field | Before | After |
|---|---|---|
| Extra | \(a, b\) associates (\(a \sim b\)) if \(a = ub\) for some unit \(u\). | \(a, b\) associates (\(a \sim b\)) if \(a = ub\) for some unit \(u\).<br><br><b>Proof sketch:<br></b><div><ol><li> <div>Consider a nonzero, nonunit \(a \in R\).</div> </li><li> <div>If a is irreducible, we are done.</div> </li><li> <div>Otherwise, \(a = bc\) with both \(b,c\) nonunits.</div> </li><li> <div>By the Euclidean property, we may assume </div>\(\delta(b), \delta(c) < \delta(a)\).</li><li> <div>If either factor is reducible, factor it further.</div> </li><li> <div>This process <b>must terminate</b>, since \(\delta\) takes values in \(\mathbb{N}\) and strictly decreases.</div></li></ol></div> |
Note 2: ETH::DiskMat
Note Type: Horvath Cloze
GUID:
Mqpm#lUsGl
Before
Front
A function \(f: A \rightarrow B\) has a right inverse if and only if \(f\) is surjective.
Back
A function \(f: A \rightarrow B\) has a right inverse if and only if \(f\) is surjective.
After
Front
A function \(f: A \rightarrow B\) has a right inverse if and only if \(f\) is surjective (not in script).
Back
A function \(f: A \rightarrow B\) has a right inverse if and only if \(f\) is surjective (not in script).
Field-by-field Comparison
| Field | Before | After |
|---|---|---|
| Text | <p>A function \(f: A \rightarrow B\) has a {{c1::right inverse}} if and only if \(f\) is {{c2::surjective}}.</p> | <p>A function \(f: A \rightarrow B\) has a {{c1::right inverse}} if and only if \(f\) is {{c2::surjective}} (not in script).</p> |
Note 3: ETH::DiskMat
Note Type: Horvath Cloze
GUID:
Qn4Vs7Ck2H
Before
Front
Back
- A set of symbols \(\mathcal{Z} \subseteq \Lambda\)
- \(\Lambda\) is the "alphabet" or collection of all available symbols
- \(\mathcal{Z}\) is the subset of symbols we're actually interpreting
- A domain for each symbol
- For each symbol in \(\mathcal{Z}\), there's a set of possible values it could take
- Often the domain is defined in terms of the universe \(U\) where a symbol can be a function, predicate or element of \(U\).
- An assignment function
- For each symbol in \(\mathcal{Z}\), the function picks one specific value from its domain
- This gives meaning to each symbol
After
Front
Back
- A set of symbols \(\mathcal{Z} \subseteq \Lambda\)
- \(\Lambda\) is the "alphabet" or collection of all available symbols
- \(\mathcal{Z}\) is the subset of symbols we're actually interpreting
- A domain for each symbol
- For each symbol in \(\mathcal{Z}\), there's a set of possible values it could take
- Often the domain is defined in terms of the universe \(U\) where a symbol can be a function, predicate or element of \(U\).
- An assignment function
- For each symbol in \(\mathcal{Z}\), the function picks one specific value from its domain
- This gives meaning to each symbol
- one big assignment function over typed symbols, or
- a structured tuple that spells out those assignments separately.
Field-by-field Comparison
| Field | Before | After |
|---|---|---|
| Extra | <ol><li>< |
<ol><li><b>A set of symbols</b> \(\mathcal{Z} \subseteq \Lambda\)<ul> <li>\(\Lambda\) is the "alphabet" or collection of all available symbols </li> <li>\(\mathcal{Z}\) is the subset of symbols we're actually interpreting </li> </ul> </li> <li><b>A domain for each symbol</b> <ul> <li>For each symbol in \(\mathcal{Z}\), there's a set of possible values it could take </li> <li>Often the domain is defined in terms of the <i>universe</i> \(U\) where a symbol can be a function, predicate or element of \(U\).<br><ol></ol></li> </ul> </li> <li><b>An assignment function</b> </li><ul> <li>For each symbol in \(\mathcal{Z}\), the function picks one specific value from its domain </li> <li>This gives meaning to each symbol</li></ul></ol><b>An interpretation can be described either as</b><br><ul><li>one big assignment function over typed symbols,<b> or</b><br></li><li>a structured tuple that spells out those assignments separately.</li></ul><ol> <h2></h2></ol> |
Note 4: ETH::DiskMat
Note Type: Horvath Cloze
GUID:
s*8T*K?3f=
Before
Front
A function \(f: A \rightarrow B\) has a left inverse if and only if \(f\) is injective.
Back
A function \(f: A \rightarrow B\) has a left inverse if and only if \(f\) is injective.
After
Front
A function \(f: A \rightarrow B\) has a left inverse if and only if \(f\) is injective (not in script).
Back
A function \(f: A \rightarrow B\) has a left inverse if and only if \(f\) is injective (not in script).
Field-by-field Comparison
| Field | Before | After |
|---|---|---|
| Text | <p>A function \(f: A \rightarrow B\) has a {{c1::left inverse}} if and only if \(f\) is {{c2::injective}}.</p> | <p>A function \(f: A \rightarrow B\) has a {{c1::left inverse}} if and only if \(f\) is {{c2::injective}} (not in script).</p> |
Note 5: ETH::DiskMat
Note Type: Horvath Classic
GUID:
u${[$*iYrd
Before
Front
Does the uniqueness of the neutral element imply that a group is abelian (commutative)?
I.e. does \(a*e = e*a\) mean \(G\) is abelian?Back
Does the uniqueness of the neutral element imply that a group is abelian (commutative)?
I.e. does \(a*e = e*a\) mean \(G\) is abelian?No! The uniqueness of the neutral element does not imply commutativity.
Counterexample: The identity matrix \(I_3\) is the unique neutral element for the group of \(3 \times 3\) real matrices under multiplication. We have \(A \cdot I_3 = I_3 \cdot A\) for all matrices \(A\), even though matrix multiplication is not commutative in general.
After
Front
Does the uniqueness of the neutral element imply that a group is abelian (commutative)?
I.e. does \(a*e = e*a\) mean \(G\) is abelian?Back
Does the uniqueness of the neutral element imply that a group is abelian (commutative)?
I.e. does \(a*e = e*a\) mean \(G\) is abelian?No! The uniqueness of the neutral element does not imply commutativity.
Counterexample: The identity matrix \(I_3\) is the unique neutral element for the group of \(3 \times 3\) invertible real matrices under multiplication. We have \(A \cdot I_3 = I_3 \cdot A\) for all matrices \(A\), even though matrix multiplication is not commutative in general.
Field-by-field Comparison
| Field | Before | After |
|---|---|---|
| Back | <p><strong>No!</strong> The uniqueness of the neutral element does <strong>not</strong> imply commutativity.</p><p><strong>Counterexample</strong>: The identity matrix \(I_3\) is the unique neutral element for the group of |
<p><strong>No!</strong> The uniqueness of the neutral element does <strong>not</strong> imply commutativity.</p><p><strong>Counterexample</strong>: The identity matrix \(I_3\) is the unique neutral element for the group of \(3 \times 3\) <i>invertible</i> real matrices under multiplication. We have \(A \cdot I_3 = I_3 \cdot A\) for all matrices \(A\), even though matrix multiplication is <strong>not commutative</strong> in general.</p> |